From: dm1 <dmertz@...>
Date: 2005-04-22T19:39:33+09:00
Subject: Re: Clean way to dynamically expand string with "#{expression}"?

And in a more OO way, you can use

irb(main):001:0> class String
irb(main):002:1>   def interpolate(caller)
irb(main):003:2>     caller.instance_eval('"' + self + '"')
irb(main):004:2>   end
irb(main):005:1> end
=> nil
irb(main):006:0> @toto = "afdgfd"
=> "afdgfd"
irb(main):007:0> '123 #{@toto}'.interpolate(self)
=> "123 afdgfd"

ciao 

Denis

Neville Burnell wrote:

> How about:
> 
> irb(main):001:0> n = 1
> => 1
> irb(main):002:0> s = 'n = #{n}'
> => "n = \#{n}"
> irb(main):003:0> puts eval('"' + s + '"')
> n = 1
> => nil
> 
> -----Original Message-----
> From: Taisuke Yamada [mailto:tyamadajp@list.rakugaki.org]
> Sent: Friday, 22 April 2005 4:35 PM
> To: ruby-talk ML
> Subject: Clean way to dynamically expand string with "#{expression}"?
> 
> Hi.
> 
> I'm trying to find a clean way to expand string with "#{...}".
> What I want to do is essentially as follows:
> 
>   data = 123
>   expr = 'data = #{data}'
> 
>   puts dosomething(expr)
> 
> and get 'data = 123' as a result. Actual content of 'expr' can be
> anything, as long as it is a String object.
> 
> I came up with following:
> 
>   puts eval(%Q{"#{expr.gsub('"', '\"')}"})
> 
> But this is ugly, and I'm wondering if there's some other, cleaner way
> to do the same thing.
> 
> Can anyone enlighten me?
> 
> Best Regards,
> --
> Taisuke Yamada