From: Ilias Lazaridis <ilias@...>
Date: 2005-04-20T20:49:34+09:00
Subject: Re: [EVALUATION] - E03d - The Ruby Object Model (End Game)

Carlos wrote:
> [Ilias Lazaridis <ilias@lazaridis.com>, 2005-04-20 11.24 CEST]
> [...]
> 
>>"Class"  is the _class_ of "Class",  not its metaclass.
>>
>>-
>>
>>the above diagramm shows a "(Class)", which is documented as a "metaclass".
>>
>>How do I access this class?
> 
> class<<Class;self;end
> 
> $ ruby -e 'p class<<Class;self;end'
> #<Class:Class>
> 
>>the above diagramm shows a "(Object)", which inherits from "Class".
>>
>>how do I call "(Object).superclass"?
> 
> 
> class<<Object;self;end
> 
> $ ruby -e 'p class<<Object;self;end.superclass'
> Class

(class<<Object; self; end).superclass

ok, fine.

-

How do I include the construct:

(class<<Object; self; end)

conveniently into the definition of "Class"?

I like to have <class>.Meta available in each class.

-

I'm a newcomer, my try is this one:

class Class
   def Meta()
     @Meta ||= (class<<self.class;self;end)
   end
end

but it fails

p Talker.Meta.object_id               => 20763792
p (class<<Talker;self;end).object_id  => 20679384

..

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