From: Nikolai Weibull <mailing-lists.ruby-talk@...>
Date: 2005-04-14T03:02:40+09:00
Subject: Re: pattern matching question

Tony Targonski, April 14:

> > I' mtrying to match a pattern like this one : 297,12^[2 where 297,12
> > is the grand total.

Are you sure all numbers will be formatted in the \d+,\d+ format?  What
about . in the first set?  What about numbers lacking the decimal part?

> your_text.scan(/([0-9]+,[0-9]+)\^\[2/)

> Will return [["297,12"]], so you might want to stick a .flatten[0] in
> there if you know you'll have only a single match.

Use (?:…) instead (and \d as it's a lot faster and clearer):

        your_text.scan(/(?:\d+,\d+)\^\[2/)

Enjoy,
        nikolai

-- 
Nikolai Weibull: now available free of charge at http://bitwi.se/!
Born in Chicago, IL USA; currently residing in Gothenburg, Sweden.
main(){printf(&linux["\021%six\012\0"],(linux)["have"]+"fun"-97);}