From: ts <decoux@...>
Date: 2001-04-17T14:08:45+09:00
Subject: [ruby-talk:13728] Re: operator +

>>>>> "J" == Johann Hibschman <johann@physics.berkeley.edu> writes:

J> (defun add ((s number) (op TridiagonalOperator))
J>   ..)
J> (defun add ((op TridiagonalOperator) (s number))
J>  ..)
J> (defun add ((op TridiagonalOperator) (v Vector))
J>  ..)
J> (defun add ((v Vector) (op TridiagonalOperator))
J>  ..)

 It's easy to add this in ruby

J> etc., and the compiler will automatically dispatch to the right
J> method. 

 The problem is here, the dispatch is made at runtime (and not compile
 time). This mean that probably you end with something slow


Guy Decoux