From: Martin DeMello <martindemello@...>
Date: 2005-03-21T20:14:50+09:00
Subject: Re: Fibonacci Benchmark Correction

Mathieu Bouchard <matju@sympatico.ca> wrote:
> so  f(-x)=+f(x) for x=0 mod 2
> and f(-x)=-f(x) for x=1 mod 2

Oh, I see what you mean. I got confused by your use of "f(x) for even
x" - in effect, you're referring to two separate functions, one defined
over the even integers and one over the odds.

martin