From: "Cs. Henk" <csaba-ml@...>
Date: 2005-03-12T02:32:47+09:00
Subject: Re: Is iterating in lock-step possible?

On Fri, Mar 11, 2005 at 12:41:33AM +0900, William Morgan wrote:
> ruby -rgenerator -rbenchmark -e 'a=(1..100000).map{|x|x};g=Generator.new(a);[
>   lambda { a.each { |x| x } },
>   lambda { while g.next?; g.next; end },
> ].each {|pr| puts Benchmark.measure(&pr) }'
>   0.030000   0.000000   0.030000 (  0.027388)
>  10.380000   1.190000  11.570000 ( 11.612888)

It's a bit faster if you do 

begin
  while g.next; end
rescue EOFError
end

Not with magnitudes, tho.

Csaba