From: pete@... (Pete Kernan)
Date: 2001-03-30T02:10:04+09:00
Subject: [ruby-talk:13330] Re: A subtle Hash bug

On Thu, 29 Mar 2001 23:11:03 +0900, Christoph Rippel pontificated:
+ my reason for preferring the ladder is that the combination of
+ (-0.0 == 0.0) but (1/-0.0) != (1/0.0) seems somewhat dubious to me

 1/0.0 == 1/0.0 is dubious enough. is this a cardinality test? :)

% ruby -le 'p (1/0.0 == 1/0.0)'
true

i prefer 
%  ruby -le 'p (1/0 == 1/0)'
-e:1:in `/': divided by 0 (ZeroDivisionError)
        from -e:1




-- 
ruby -F- -e '$, = $; . sub /./, " Another "; print %w.Just Rewbie .. join'