From: Robert Klemme <bob.news@...>
Date: 2005-02-10T07:55:05+09:00
Subject: Re: How to mimic Perl's `s///' in Ruby?


"Jos Backus" <jos@catnook.com> schrieb im Newsbeitrag 
news:20050209201021.GA47301@lizzy.catnook.com...
> Given Perl's
>
>    $_ = "123 foo";
>
>    s/^(\d+)\s+//;
>    $pid = $1;
>
>    print "$_\n$pid\n";
>
> all I can come up with is
>
>    line = "123 foo"
>
>    pid = nil
>    line.sub!(/^(\d+)\s+/) {pid = $1; ''}
>
>    puts line, pid
>
> Is there a better way perhaps?

Others have shown ways to mimic Perl - even so far as to include the 
trailing semicolons.  I don't know why you want to mimic Perl, but here's 
how I'd do it in Ruby:

if /^(\d+)\s+(.*)$/ =~ str
  pid, name = $1, $2
else
  # no match
end

Or, if you expect it to always match:

raise "String error: #{str}" unless /^(\d+)\s+(.*)$/ =~ str
pid, name = $1, $2

Kind regards

    robert