From: georgesawyer <georgesawyer2@...>
Date: 2005-01-08T06:56:27+09:00
Subject: Re: what's the Ruby way to do this?

At first, I thought:
a ='The quick  red fox jumps over the lazy brown fat hog.'
p (b =a.split).size < 10 ?b :(b.first 10) <<'...'

# Result:
	=>["The", "quick", "red", "fox", "jumps", "over", "the", "lazy", "brown",
"fat", "..."]

# Then I considered its real use and changed it to:
p a='This is  a test sentence that I just now made up.'
b =a.strip
last =-1 # Start before.
10.times do
	last =b.index(	# This word's last character.
	%r{ # Regular expression specifying:
		\w	# A word character,
		\b	# Immediately followed by a word boundary.
	}x ,		# Ignore spaces and newlines above.
	last +1)	# Start with next character.
	# Debug code: print last ,b[last].chr ,"\n"
end
p (last >=b.size) ?b :b[ 0..last] +'...'

__END__
#Result:
	=>"This is  a test sentence that I just now made up."
	=>"This is  a test sentence that I just now made..."