From: Alex Fenton <alex@...>
Date: 2004-12-15T07:02:16+09:00
Subject: no-argument sort()

Hi

I tried the code below- I thought

[a, b].sort

was always the same as

[a, b].sort { | x, y | x <=> y }

and don't understand why it's not in this case. The String subclass 
method doesn't seem to get called in the no-arg version?

Thanks
alex

---
class Fragment < String
   def <=>(other)
     p "Called subclassed method"
     = super
   end
end

a = Fragment.new('abc')
x = Fragment.new('xyz')

p a < x
p x <= a
p [x, a].sort
p [x, a].sort { | i, j | i <=> j }