From: "Mauricio Fernández" <batsman.geo@...>
Date: 2004-12-08T20:35:22+09:00
Subject: Re: Ruby 2.0

On Wed, Dec 08, 2004 at 02:52:35PM +0900, Oliver Cromm wrote:
> > Some obvious modifications:
> > 
> > ruby -rmatrix -le'a=[1];10.times{|n|print" "*(9-n)*3,"%3d   "*a.size%a;a<<0;a=(
> > Vector[*a]+Vector[*a.reverse]).to_a}'
> 
> Obvious once you know the stuff - I'm learning!
>  
> > There's still potential for further optimization but I prefer to zzzZZ.
> 
> a.size = n+1, better yet:

Nice catch, we save 1 char.

>   ruby -rmatrix -le'a=[1];1.upto(10){|n|print" "*(10-n)*3,"%3d   "*n%a
>   a<<0;a=(Vector[*a]+Vector[*a.reverse]).to_a}'
> 
> I found the Vector stuff /kakkou ii/, but without, it's shorter.

Yes, that's what I had in mind. 

> Accepting the extra indent, my shortest now is:
> 
>   ruby -le'a=[];10.times{|n|a<<1;print" "*(9-n)*3,"%6d"*(n+1)%a
>   n.downto(1){|i|a[i]+=a[i-1]}}'

    ruby -e'a=[];10.times{|n|a<<1;puts" "*(9-n)*3+"%6d"*(n+1)%a;n.
    times{|i|a[n]+=a[n-=1]}}'

It can be made to fit in a canonical 80-char line (actually 78):

a=[];10.times{|n|a<<1;puts" "*(9-n)*3+"%6d"*(n+1)%a;n.times{|i|a[n]+=a[n-=1]}}

The indentation code might allow further optimization.

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