From: Matt Maycock <ummaycoc@...>
Date: 2004-10-18T23:51:58+09:00
Subject: Re: DID YOU KNOW? -- break can return a value?

Well, he was right if we consider the additive group Z / 2 where 0 = 2
= 4... remember, you're not mistaken - you're clever.  :-)

~Me!


On Mon, 18 Oct 2004 22:40:27 +0900, trans.  (T. Onoma)
<transami@runbox.com> wrote:
> On Monday 18 October 2004 09:10 am, Florian Frank wrote:
> 
> 
> | On 2004-10-18 21:39:40 +0900, zuzu wrote:
> | > also, quite right dave, what gives with the "trailing off the edge of
> | > a procedure 'return' " producing a "value" of 4?  perhaps that's the
> | > point; what exactly is going on when passing arguments into the break
> | > function/keyword?
> |
> | Whatever it may be, I am quite sure 1 + 1 is still equal to 2.
> 
> :-) Yes, that's a typo, a would be 2, not 4. Strange how easy that is to
> overlook!
> 
> T.
> 
> 


-- 
There's no word in the English language for what you do to a dead
thing to make it stop chasing you.