From: Joao Pedrosa <joaopedrosa@...>
Date: 2004-10-12T00:09:42+09:00
Subject: Re: string replacement

Hi,

On Mon, 11 Oct 2004 11:22:52 -0300, Joao Pedrosa <joaopedrosa@gmail.com> wrote:
> Hi,
> 
> On Mon, 11 Oct 2004 23:06:58 +0900, J.Lang <jlang@ywesee.com> wrote:
> > we need to replace a  whitespace with a <br> if the string is longer
> > then 30 chars (next whitespace after 30 chars)
> >
> > does someone have a idea to programm this in ruby?

Here is my second take:

5.times{
s = 'a' * (rand * 100)
p "s (#{s.size}): #{s}"
z = ''
while s do
  if s.size <= 30
    z += s
    break
  else
    i = s[30..-1].index(' ') || s.size
    i += 30
    z += s[0..i] 
    s = s[i+1..-1]
    if s
      z += '<br />'    
    end
  end
end
p '---z---', z, '-------'
}

This time I break a string that is bigger than 30 characters into
small chunks of 30 or so characters, depending on the next blank
space, which is substituted by a <br /> tag.
If the string is big enough and has enough spaces, then it may be
broken in as many necessary chunks of 30 or so characters.

Is that it?

Cheers,
Joao