From: nobu.nokada@...
Date: 2004-10-04T09:20:03+09:00
Subject: Re: Kernel#eval taking a block

Hi,

At Sun, 3 Oct 2004 10:25:37 +0900,
trans.  (T. Onoma) wrote in [ruby-talk:114646]:
> Is there a reason Kernel#eval won't take a block? I wrote this to overcome:
> 
>   # Evaluate a Ruby source code string (or block) in the binding context
>   def evalb( str=nil, binding=nil, &blk )
>     if block_given?
>       Kernel.eval( "proc {|slf, blk| slf.instance_eval(&blk)}", 
> binding ).call( binding, blk )
>     elsif str
>       Kernel.eval( str, binding )
>     end
>   end

It's evaluated in the Binding/Proc's context, but not in the
context where it was created.  I.E., it is equivalent to

  binding.instance_eval(&blk)

except that variables `slf' and `blk' will be altered if they
exist in the context of `binding'.

Seems less meaningful.

-- 
Nobu Nakada