From: STEPHEN BECKER I V <Becker004@...>
Date: 2004-10-04T06:09:20+09:00
Subject: stack level to deep?

aaaaa
C:/Documents and Settings/IV/Desktop/crazy.rb:5:in `nextl': stack
level too deep (SystemStackError)

      from C:/Documents and Settings/IV/Desktop/crazy.rb:4:in `each'
      from C:/Documents and Settings/IV/Desktop/crazy.rb:4:in `each'
      from C:/Documents and Settings/IV/Desktop/crazy.rb:4:in `nextl'
      from C:/Documents and Settings/IV/Desktop/crazy.rb:5:in `nextl'
      from C:/Documents and Settings/IV/Desktop/crazy.rb:4:in `each'
      from C:/Documents and Settings/IV/Desktop/crazy.rb:4:in `each'
      from C:/Documents and Settings/IV/Desktop/crazy.rb:4:in `nextl'
      from C:/Documents and Settings/IV/Desktop/crazy.rb:5:in `nextl'
       ... 2083 levels...
      from C:/Documents and Settings/IV/Desktop/crazy.rb:11
      from C:/Documents and Settings/IV/Desktop/crazy.rb:10:in `each'
      from C:/Documents and Settings/IV/Desktop/crazy.rb:10:in `each'
      from C:/Documents and Settings/IV/Desktop/crazy.rb:10
Press any key to continue . . .


Is there away to increase the allowed space for the stack info?
I want to print out ever permutation of the alphabet.  I know it
sounds crazy, but i want to.

def nextl (a,d)
	if d==0 then  print a # max depth
	print "\n" end
	for i in 'a'..'z'  # add the next letter in the alphabet
	nextl(a<<i.to_s,d-1) #concat and call
	print "\n"
	end
end

for i in 'a'..'z'
	 nextl(i.to_s,4)
	 print "\n"
end 

is my code, it should print out all aaaaa,aaaab,aaaac.... 
becker