From: "trans.  (T. Onoma)" <transami@...>
Date: 2004-10-03T10:25:37+09:00
Subject: Kernel#eval taking a block

Is there a reason Kernel#eval won't take a block? I wrote this to overcome:

  # Evaluate a Ruby source code string (or block) in the binding context
  def evalb( str=nil, binding=nil, &blk )
    if block_given?
      Kernel.eval( "proc {|slf, blk| slf.instance_eval(&blk)}", 
binding ).call( binding, blk )
    elsif str
      Kernel.eval( str, binding )
    end
  end

Although, I'm not sure it's exactly right --I put it together by a bit of 
trial and error.

T.

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