From: "Brian Schröder" <ruby@...>
Date: 2004-09-28T05:41:53+09:00
Subject: Re: {newb} Each statements

ndata = ndata.split(//).map { | c | ((c-97)+rand(10))%26 }.join

But there was a thread the efficency of the  different ways to loop the 
bytes of a string some time ago.

What I'm doing is not inplace, and I'm creating two now objects on the 
way, so if efficency is important this is not perfect.

Regards,

Brian

STEPHEN BECKER I V wrote:
> nope
> 
> Z:/ruby/vernam.rb:26:in `encrypt': undefined method `map!' for
> "abcdefghijklmnop":String (NoMethodE
> rror)
>         from Z:/ruby/vernam.rb:38
> Press any key to continue . . .
> 
> 
> On Tue, 28 Sep 2004 05:22:54 +0900, James Edward Gray II
> <james@grayproductions.net> wrote:
> 
>>
>>On Sep 27, 2004, at 3:13 PM, STEPHEN BECKER I V wrote:
>>
>>
>>>Do each statements change the thing that they are using?
>>>data is a a string.
>>>##code
>>>
>>>                              ndata=data.clone
>>>              a = ndata.size-1
>>>              srand(5000)
>>>              ndata.each  do |c|
>>>                  c=((c-97)+rand(10))%26
>>>              end
>>>## code
>>>
>>>So ndata indexes are not change?  Am i doing this wrong (well i know
>>>its not working so it cant be right.)? I have it working with a while
>>>loop but i am trying to teach my self the ruby way.
>>
>>How about using:
>>
>>ndata.map! do |c|
>>       ((c-97)+rand(10))%26
>>end


-- 
Brian Schr�der
http://ruby.brian-schroeder.de/