From: "Olivier D." <purple.dot_meteor@..._dot.com>
Date: 2004-09-08T18:00:07+09:00
Subject: Re: Creating new scope

On 2004-09-08, George  Moschovitis <george.moschovitis@gmail.com> wrote:
>
> x = 0
>
> 1.times {
> x = 1
> puts x
> }
>
> puts x
>
> prints:
> 1
> 0

If I do this on my machine, it prints 1 and 1.

What version of Ruby have you installed? I have the version 1.8.1
and it works as advertised in the book "Programming Ruby" (chapter
"The Ruby Language"):
"If instead a variable of the same name is already established at the
time the block executes, the block will inherit this variable."

Your 1.times block inherits the x variable and modifies it (or maybe
it's time for me to compile Ruby version 1.8.2?)

-- 
Olivier D.