From: Zach Dennis <zdennis@...>
Date: 2004-08-18T04:55:28+09:00
Subject: Re: multiple regexp matches

According to rdoc you are mistaken.

I also think you are mistaken:

#!/usr/bin/ruby
t = "This is my 1 text"

re = /([^\s]*\s).*(\d)(\s.)/
md = re.match( t );
puts md.offset(0);
puts ""
puts md.offset( 1 );
puts ""
puts md.offset( 2 );
puts ""
puts md.offset( 3 );


It returns the correct offsets of the matches. offset(0) being the whole 
regex, offset(1) does the first subexpression, offset(2) does the second 
subexpression. It works.

Zach



Kevin Howe wrote:

>"Zach Dennis" <zdennis@mktec.com> wrote in message
>news:4122539A.1000900@mktec.com...
>  
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>>Instead of using str.scan(re) use:
>>
>>re.match( str );
>>
>>which returns a MatchData object. You can use the MatchData object's
>>offset method to find your results.....i do believe.
>>    
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>Yes that's true, but if you read the second part of my message, I'd already
>tried this:
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>>The Regexp module will return offsets, but Regexp::match only returns the
>>first match, so I'm not sure how to get the full list of matches?
>>    
>>
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