From: Austin Ziegler <halostatue@...>
Date: 2004-08-05T02:46:14+09:00
Subject: Re: YAML.load(ARGF)

On Thu, 5 Aug 2004 02:36:29 +0900, Hans Fugal <hans@fugal.net> wrote:
> Consider these two short programs:
>         ARGF.read
> and
>         require 'yaml'
>         YAML.load(ARGF)
> 
> Then call them like so:
> 
>         $ ruby foo.rb foo
> 
> The first program prints the contents of foo and exits. The second
> program waits for ^D from the terminal, and then tries to parse the YAML
> and go on with life.
> 
> I want ARGF to behave like it does in the first example, in the second
> example. Of course I could do YAML.load(ARGF.read) but that doesn't
> satisfy my curiousity. :-)

IMO, YAML.load *should* do this with ARGF because the following works:

  f = File.open("foo", "rb")
  YAML.load(f)
  f.close

-austin
-- 
Austin Ziegler * halostatue@gmail.com
               * Alternate: austin@halostatue.ca