From: Tanaka Akira <akr@...17n.org>
Date: 2002-08-13T18:02:51+09:00
Subject: [ruby-dev:18001] Re: Hash has default block?

In article <1029229143.399680.2549.nullmailer@picachu.netlab.jp>,
  matz@ruby-lang.org (Yukihiro Matsumoto) writes:

> |$BB>$K$J$$$N$+$J$!!"$H;W$C$F(B replace $B$r;n$7$F$_$?$i$3$l$O$=$b$=$b(B
> |default $B$rCV$-49$($J$$$h$&$G$9$M!#(B
> 
> $B$3$l$bD>$7$F$*$-$^$9!#(B

$B$&$%$`!#0U?^$5$l$6$k5sF0$G$7$?$+!#(B

$B$H$9$k$H!"(Bundocumented $B$J(B Hash.[] $B$N5!G=$r;H$C$?(B

% ruby -e 'h = Hash.new(1); p Hash[h][0]'
nil

$B$b$G$9$+$M!#(B
-- 
[$BEDCf(B $BE/(B][$B$?$J$+(B $B$"$-$i(B][Tanaka Akira]
$B!V$U$($m(B! $B$o$+$a$A$c$s:n@o$G$9$(C"=$B!W(B(Little Worker, $B7KM7@84](B)