From: Tanaka Akira <akr@...17n.org>
Date: 2002-08-13T14:58:09+09:00
Subject: [ruby-dev:17992] Re: Hash has default block?

In article <1029217836.750863.1401.nullmailer@picachu.netlab.jp>,
  matz@ruby-lang.org (Yukihiro Matsumoto) writes:

> $B$"!"$G$b!"(Bdefault_*block* $B$G$O$J$$$N$G$O$J$$$+$H!#(Bblock$B$O9=(B
> $BJ8>e$N(Bbegin ... end$B$N$3$H$G!"<jB3$-%*%V%8%'%/%H$N$3$H$G$O$J(B
> $B$$$N$G!#(Bdefault_proc$B$+$J$"!#(B

$B$=$C$+!#$=$l$O$=$&$G$9$M!#(B

$B0JA0$N5DO@$rFI$s$@$N$G$9$,!"$^$!!"(Bdefault_proc $B$,4V0c$C$F$$$J$$L>A0$H(B
$B$7$F$O0lHV3N<B$J5$$,$7$^$9!#(B
-- 
[$BEDCf(B $BE/(B][$B$?$J$+(B $B$"$-$i(B][Tanaka Akira]
$B!V$U$($m(B! $B$o$+$a$A$c$s:n@o$G$9$(C"=$B!W(B(Little Worker, $B7KM7@84](B)