From: Tanaka Akira Date: 2002-06-17T15:48:45+09:00 Subject: [ruby-dev:17481] Re: ternary operator and char literal (Re: parse error with `true || break ? 0 : 1' (PR#261)) In article <200206160749.g5G7nI231269@sharui.nakada.kanuma.tochigi.jp>, nobu.nakada@nifty.ne.jp writes: > $BA0 $B7h$a$kI,MW$,$"$k$H;W$$$^$9!#8=>u$G$O!"@hF,$N0l%P%$%H$@$1$,%j%F(B > $B%i%k07$$$G$9!#(B > > $ ruby -v -e 'p ?$B$"(B' > ruby 1.7.2 (2002-06-15) [i686-linux] > -e:1: Invalid char `\242' in expression $B$J$k$[$I!#$^$!!"%^%k%A%P%$%H$@$m$&$,J8;z$OJ8;z$H$$$&$3$H$G$R$H$+$?$^$j(B $B$K$9$k$N$,=gEv$@$H;W$$$^$9$,!#$?$@!"$I$s$J@0?t$K$9$l$P$$$$$s$G$7$g$&(B $B$M$'!#(B > $B8e