Re: Again Range=== bug

On Sun, Aug 13, 2006 at 12:34:58PM +0200, [e-mail] wrote:
> Hi --
> 
> On Sun, 13 Aug 2006, Ondrej Bilka wrote:
> 
> >On Sun, Aug 13, 2006 at 10:25:03AM +0200, [e-mail] wrote:
> >>Hi,
> >>
> >>At Sun, 13 Aug 2006 15:59:24 +0900,
> >>Ondrej Bilka wrote in [ruby-core:08609]:
> >>>Problem of discrete membership at Range#=== is that it returns unexpected
> >>>result when treating float-like Classes. Class Time is represented as
> >>>float so
> >>>(Time.new...Time.new+5)===Time.new returns false.
> >>
> >>Really?
> >>
> >>$ ruby -ve 't = Time.new; p((t...t+5)===t+1)'
> >>ruby 1.9.0 (2006-08-12) [i686-linux]
> >>true
> >>
> >>And Time isn't float.
> >>
> >>>I choose Comparable#between? but I rather change its
> >>>arguments to low.between?(value, high,excl) because now value
> >>>doesnt know what range represents and can only guess that
> >>>they are same type.(I dont know how frequently its used. )
> >>
> >>Double dispatch may be considerable, but that change of
> >>"between?" feels doubtful to me.
> >>
> >>--
> >>Nobu Nakada
> >>
> >Can someone simply cut my text and paste it???
> 
> irb(main):010:0> (Time.new...Time.new+5)===Time.new
> => true
> irb(main):011:0> RUBY_VERSION
> => "1.8.4"
> 
> >If you are lazy try
> >t=Time.new
> >(t...t+5.5)===t+2.3
> >which return false too
> 
> irb(main):012:0> t = Time.new
> => Sun Aug 13 06:34:02 EDT 2006
> irb(main):013:0> (t...t+5.5)===t+2.3
> => true
> 
> 
> David
> 
> -- 
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>

My bad assumption that 1.9.0 is at sync with 1.8.4
puts RUBY_VERSION
puts (Time.new...Time.new+5)===Time.new
1.9.0
false