From: herwin@... Date: 2016-11-22T11:39:13+00:00 Subject: [ruby-core:78254] [Ruby trunk Feature#12969] Allow optional parameter in String#strip and related Issue #12969 has been updated by Herwin Quarantainenet. The concrete use case that I got was that I wanted to replace all trailing whitespace, but leave tabs/newlines etc untouched. The current code looks like this: ```ruby newstr = str.sub(/ +$/, '') ``` I tried to see if there was a more suitable method in String to do this, but both `String#rstrip` and `String#chomp` case close to what I needed here, but no cigar. ---------------------------------------- Feature #12969: Allow optional parameter in String#strip and related https://bugs.ruby-lang.org/issues/12969#change-61618 * Author: Herwin Quarantainenet * Status: Open * Priority: Normal * Assignee: ---------------------------------------- `String#strip` and related methods have a hardcoded match on whitespace, defined as "null, horizontal tab, line feed, vertical tab, form feed, carriage return, space". It would be nice to allow a parameter to specify the characters you want to strip. This would result in a kind of marriage between `String#delete` and `String#chomp`. The first one is an example on how to specify character classes, the second one is an example on how to pass an optional parameter. Examples how this would work: ```ruby "hellooo ".rstrip #=> "hellooo" "hellooo ".rstrip(" ") #=> "hellooo" "hellooo ".rstrip(" o") #=> "hell" "hellooo ".rstrip("o ") #=> "hell" "hellooo ".rstrip("o") #=> "hellooo " "hellooo ".chomp(" ") #=> "hellooo ", only replaces one character, thus not a sensible alternative ``` The same behaviour can be achieved by using `String#sub` and the correct anchors, but I think an optional parameter to `String#strip` is cleaner to read. It's probably faster too, since we don't have to initialize a regex state machine. -- https://bugs.ruby-lang.org/ Unsubscribe: