From: Brian Mitchell <binary42@...>
Date: 2006-03-17T04:49:16+09:00
Subject: Re: [ ruby-Bugs-3843 ] "not" operator used in expression that is a method parameter can generate syntax error

On 3/16/06, mathew <meta@pobox.com> wrote:
> I still don't understand why foo(!(1<2)) is OK, but foo(not(1<2)) isn't.
>
> The pickaxe says that the only difference between '!' and 'not' is
> precedence, and in these two cases everything is explicitly bracketed so
> precedence shouldn't be involved.
>
> What am I missing?

foo(not(1<2), 3)
or more clearly bound if I understand Matz correctly:
foo(not((1<2),3))

not has meaningless semantics in this case. If not was allowed only in
single argument calls, this might lead to confusion.

Brian.