From: "David A. Black" <dblack@...>
Date: 2005-10-07T20:28:59+09:00
Subject: yield and call not identical?

Hi --

I'd always thought that yield was just syntactic sugar for calling the
block, but I notice there's at least one difference:

   def x(&b)
     b.call
     puts "Still here (x)"
   end

   def y
     yield
     puts "Still here (y)"
   end

   lam = lambda { return }

   x &lam
   y &lam

   Output:

   Still here (x)
   retu.rb:11: unexpected return (LocalJumpError)
           from retu.rb:11:in `y'
           from retu.rb:14


I'm trying to sort out all the return/Proc/lambda combinations... and
this one struck me as odd.


David

-- 
David A. Black
dblack@wobblini.net