From: "alexeymuranov (Alexey Muranov)" Date: 2013-08-19T06:24:39+09:00 Subject: [ruby-core:56732] [ruby-trunk - Feature #7739] Define Hash#| as Hash#reverse_merge in Rails Issue #7739 has been updated by alexeymuranov (Alexey Muranov). rosenfeld (Rodrigo Rosenfeld Rosas) wrote: > I'm not sure to be honest. I believe that's because in my head when I perform set1 |= set2 I read it as "discard any duplicate values in set2 when merging the values to set1" or "merge all values from set2 that are not present in set1". I never think of it as "remove any values in set1 that also happen to be present in set 2 then add all values of set2 to set1". How it this different from the proposed behavior for hashes? hash1 |= hash2 discards any duplicate values in hash2 and adds the rest to hash1. ---------------------------------------- Feature #7739: Define Hash#| as Hash#reverse_merge in Rails https://bugs.ruby-lang.org/issues/7739#change-41261 Author: alexeymuranov (Alexey Muranov) Status: Assigned Priority: Normal Assignee: matz (Yukihiro Matsumoto) Category: core Target version: next minor =begin I suggest for to define (({Hash#|})) as (({Hash#reverse_merge})) in ((*Rails*)), in my opinion this would correspond nicely to (({Set#|})), to the logical (({#||})) and to the bitwise (({#|})): { :a => 1, :b => 2 } | { :b => 1, :c => 2 } # => { :a => 1, :b => 1, :c => 2 } =end -- http://bugs.ruby-lang.org/