From: Rodrigo Rosenfeld Rosas <rr.rosas@...>
Date: 2012-03-06T23:03:21+09:00
Subject: [ruby-core:43095] Re: "\\".gsub("\\", "\\\\") == "\\" ?!!!

Thanks for your explanation Xavier! Sorry for posting this in this list.

Cheers,
Rodrigo.

Em 06-03-2012 10:54, Xavier Noria escreveu:
> A literal passed as second argument to gsub goes over two
> unescaping passes: the first one is the one as a string literal. The
> second one is the one done by gsub itself since it has to detect
> backreferences in the string object (note that a string object has no
> escaping rules by itself, only literals have).
>
> So, \\\\ becomes \\ after the first pass, and that becomes \ after the
> second pass.
>
> To get a double backslash you need to escape twice, one per pass.
>
> I normally use the block form of gsub to avoid so many backslashes.
>