[ruby-core:43073] [ruby-trunk - Bug #6067] Conditional assignment of a nested constant raises a SyntaxError

Issue #6067 has been updated by Barry Allard.


One would think it would evaluate similar to:

(A::X = 1 if ! defined? A::X or A::X.nil? ; A::X)


For comparison, these also fail:

    ruby -e 'module A; end; p A::X = 2; p A::X ||= 1'
    ruby -e 'module B module Inner end end; B::Inner::X ||= 4; p B::Inner::X'


Also, these correctly succeed:

    ruby -e 'module F X ||= 2 end; p F::X'
    ruby -e 'module G class Foo; X ||= 3 end end; p G::Foo::X'
    ruby -e 'module H module Inner end end; H::Inner::X = 4; p H::Inner::X'
----------------------------------------
Bug #6067: Conditional assignment of a nested constant raises a SyntaxError
https://bugs.ruby-lang.org/issues/6067

Author: Brian Ford
Status: Open
Priority: Normal
Assignee: 
Category: 
Target version: 
ruby -v: ruby 1.9.3p125 (2012-02-16 revision 34643) [x86_64-darwin10.8.0]


I can conditionally assign a simple constant:

$ ruby -v -e 'p X ||= 1'
ruby 1.9.3p125 (2012-02-16 revision 34643) [x86_64-darwin10.8.0]
1

However, conditional assignment of a nested constant raises a SyntaxError:

$ ruby -v -e 'module A; end; p A::X ||= 1'
ruby 1.9.3p125 (2012-02-16 revision 34643) [x86_64-darwin10.8.0]
-e:1: constant re-assignment

But I can assign the constant unconditionally, of course:

$ ruby -v -e 'module A; end; p A::X = 1'
ruby 1.9.3p125 (2012-02-16 revision 34643) [x86_64-darwin10.8.0]
1

Is this a bug?

Thanks,
Brian


-- 
http://bugs.ruby-lang.org/