[ruby-core:28554] Re: [Bug #2945] Regexp#=== is failed by an exception when the exception is occurred in method_missing

Hi,

On 2010/03/08, at 15:46, Yukihiro Matsumoto wrote:

> Hi,
> 
> In message "Re: [ruby-core:28552] [Bug #2945] Regexp#=== is failed by an exception when the exception is occurred in method_missing"
>    on Mon, 8 Mar 2010 15:32:24 +0900, Kenta Murata <[e-mail]> writes:
> 
> |When an exception is occurred in method_missing,
> |Regexp#=== is failed by the exception.
> |Is this valid behavior?
> 
> I think so.  What makes you think it's invalid?

I think the present behavior is unfortunate the following case.
I don't expect raising exception, but printing 2.

  o1 = Object.new
  class << o1
    def method_missing(*args)
      raise "XXX"
    end
  end
  
  case o1
  when /aaa/
    puts 1
  when o
    puts 2
  end
  #=> `method_missing': XXX (RuntimeError)

--
Kenta Murata
OpenPGP FP = FA26 35D7 4F98 3498 0810 E0D5 F213 966F E9EB 0BCC

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