From: Michael Klishin <michael.s.klishin@...>
Date: 2008-11-29T22:24:47+09:00
Subject: [ruby-core:20166] Re: \Z? in regular expression in 1.9.1


On 29.11.2008, at 15:13, David A. Black wrote:

> Also, it's not allowed unconditionally in 1.8:
>
>>> /\Z?/
> SyntaxError: compile error
> (irb):5: invalid regular expression; there's no previous pattern, to
> which '?' would define cardinality at 3: /\Z?/

I only asked because I noticed the following difference between 1.8  
and 1.9.1:

http://gist.github.com/30237

1.9.1 behavior makes sense to me.

MK