From: "Radosław Bułat" <radek.bulat@...>
Date: 2008-11-29T19:42:09+09:00
Subject: [ruby-core:20162] Re: \Z? in regular expression in 1.9.1

On Sat, Nov 29, 2008 at 12:14 AM, Michael Klishin
<michael.s.klishin@gmail.com> wrote:
> I noticed that the following reg exp causes syntax error in 1.9.1 (I use tip
> of the branch):
>
> /\n(\.\/)?(.*spec\.rb):[\d]+:\Z?/
>
> To reproduce, just fire up irb of 1.9.1 and try to assign this literal to
> some variable.
>
> The problem is with ? quantifier following \Z. I could not find any
> information about this
> restriction on the web and have no Mastering regular expressions book at
> hand.
>
> Could someone shed some light on whether it is 1.9.1 engine restriction,
> general regular expressions
> restriction or possible 1.9.1 bug?
>
> Just in case: this regexp comes from autospec in RSpec.

I think this is expected behavior. "\Z" is zero width assertion so it
doesn't make sense to mix it with "?" operator. Your regexp is the
same as:
 /\n(\.\/)?(.*spec\.rb):[\d]+:/

-- 
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Rados�aw Bu�at
http://radarek.jogger.pl - m�j blog