From: Trans <transfire@...>
Date: 2008-01-09T11:41:19+09:00
Subject: Re: p returning its argument?



On Jan 8, 9:35�pm, "David A. Black" <dbl...@rubypal.com> wrote:
> Hi --
>
> On Wed, 9 Jan 2008, Nikolai Weibull wrote:
> > On Jan 9, 2008 1:14 AM, David A. Black <dbl...@rubypal.com> wrote:
>
> >> I might have missed this somewhere, but I'm wondering why p is now
> >> returning its argument
>
> > To make it easy to drop in a p in a chain of methods.
>
> It's a private method, though, so it can't go in the middle of a
> chain, and it's also functional (i.e., p 1, rather than 1.p). I guess
> it could go at the beginning of a chain. I'm not sure I'm getting it,
> thoguh.

  def x
    return r
  end

  def x
    return p(r)
  end

And

  x = foo

  x = p(foo)

And

  foo(bar(baz))

  foo(bar(p(baz))

T.