[ruby-core:120167] [Ruby master Bug#20938] Percent String literal delimiter impacts string contents with parse.y

Issue #20938 has been updated by tenderlovemaking (Aaron Patterson).


tenderlovemaking (Aaron Patterson) wrote in #note-5:
> nobu (Nobuyoshi Nakada) wrote in #note-3:
> > Prism seems to cut the string content out, then convert EOLs.
> > 
> > The conversion of EOL is lower layer than parsing, so the result of "program1" should be "1_" without "\n".
> 
> Sorry, I don't understand. Can you explain more?  Why does EOL conversion impact `program1` but not `program2`?

I think I understand, but I will try to explain.  In `program1` EOL conversion first changes it to `"%\n1_\n\n"`, so the second `\n` becomes the delimiter?

Is that correct?

Thanks

----------------------------------------
Bug #20938: Percent String literal delimiter impacts string contents with parse.y
https://bugs.ruby-lang.org/issues/20938#change-110925

* Author: eightbitraptor (Matt V-H)
* Status: Assigned
* Assignee: prism
* ruby -v: ruby 3.4.0dev (2024-11-28T09:19:02Z master 31a3e87777) +PRISM +GC [arm64-darwin24]
* Backport: 3.1: UNKNOWN, 3.2: UNKNOWN, 3.3: UNKNOWN
----------------------------------------
The following code defines 2 programs that declare string literals using `%` and a single byte delimiter. I'd expect these programs to have the same output no matter which delimiter is used.

With Prism, both programs output the same value (the string content: `1_\n`), but using parse.y the output values differ depending on the delimiter.

Are the outputs supposed to be the same or different?

```
program1 = "%\n1_\r\n\n" # => parse.y: 1_, prism: "1_\n"
program2 = "%'1_\r\n'"   # => "1_\n"

p eval(program1)
p eval(program2)
```

[[Github Issue]](https://github.com/ruby/prism/pull/3290)



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