[ruby-core:120001] [Ruby master Bug#20790] Syntax acceptance of `*x = p rescue p 1` is different between parse.y and prism

Issue #20790 has been updated by ydah (Yudai Takada).


I checked if it is feasible with parse.y: https://github.com/ydah/ruby/commit/50100c136ac4bbe379b2c360994b739227610e17

I have been able to confirm that the following are feasible with the modifications shown above.

```ruby
                    # current parse.y behavior   # matz's preference
*x = p rescue p 1   # (*x = p) rescue (p 1)      # *x = (p rescue (p 1))
*x = p 1 rescue p 1 # (*x = p 1) rescue (p 1)    # *x = ((p 1) rescue (p 1))
a, b = p rescue p   # a, b = (p rescue p)        # as is
x = p rescue p      # x = (p rescue p)           # as is
x = p 1 rescue p 1  # x = ((p 1) rescue (p 1))   # as is
```

The following are still under investigation for feasibility.

```ruby
                    # current parse.y behavior   # matz's preference
x = p rescue p 1    # x = (p rescue p) 1 (ERROR) # x = (p rescue p 1)
```

----------------------------------------
Bug #20790: Syntax acceptance of `*x = p rescue p 1` is different between parse.y and prism
https://bugs.ruby-lang.org/issues/20790#change-110745

* Author: tompng (tomoya ishida)
* Status: Open
* ruby -v: ruby 3.4.0dev (2024-10-09T03:27:05Z master ed11a244dd) +PRISM [x86_64-linux]
* Backport: 3.1: UNKNOWN, 3.2: UNKNOWN, 3.3: UNKNOWN
----------------------------------------
~~~ruby
*x = p rescue p 1 # syntax error in prism
*x = p 1 rescue p 1 # both syntax ok
x = p rescue p 1 # both syntax error
x = p 1 rescue p 1 # both syntax ok
~~~
Which is correct? If `*x = p rescue p 1` is syntax valid, should `x = p rescue p 1` also be syntax valid?




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