[ruby-core:118317] [Ruby master Feature#20580] Pipe Operator accepting lambda

Issue #20580 has been updated by martinosis (Martin Chabot).

Subject changed from Pipe Operator accepting lamnda to Pipe Operator accepting lambda

Description

I think that the previously pipe operator suggested syntax was not reflecting the actual pipe operator in functional programming languages.

In Elixir, Elm, F# etc. The pipe operator takes a value and applies it on the lambda at the right of the operator. Example:

```
add_one = -> a { a + 1 }
add_two = -> a { a + 2 }

2 |> add_one |> add_two == 5
```

In combination with the >> operator, some interesting thing can be done.

```
2 |> add_one >> add_two
```

you can refactor to

```
add_tree = add_one >> add_two
2 |> add_tree
```

We can use the `then` method on Object to do the equivalent. However this takes more characters and you need to put the closing bracket at the end of the line.

```
2.then(&add_one >> add_tree)
```

The suggested syntax would support the actual meaning of the pipe operators in functional languages.




----------------------------------------
Feature #20580: Pipe Operator accepting lambda
https://bugs.ruby-lang.org/issues/20580#change-108823

* Author: martinosis (Martin Chabot)
* Status: Open
----------------------------------------
I think that the pipe operator was not reflecting the actual pipe operator in functional programming language. 

In Elixir, Elm, F# etc. The pipe operator takes a value and applies it on the lambda at the right of the operator. Example

```
add_one = -> a { a + 1 }
add_two = -> a { a + 2 }

2 |> add_one |> add_two == 5
```

In combination with the >> operator, some interesting thing can be done. 

```
2 |> add_one >> add_two
```

you can refactor to 

```
add_tree = add_one >> add_two
2 |> add_tree
```

I currently use the `then` method on Object to do the equivalent. However this takes more characters and you need to put the closing bracket at the end of the line.

```
2.then(&add_one >> add_tree)
```





-- 
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