From: "arian (Arian Faurtosh) via ruby-core" <ruby-core@...>
Date: 2023-11-28T17:49:29+00:00
Subject: [ruby-core:115518] [Ruby master Bug#20026] Ruby doesn't throw a syntax error when rescuing with ||

Issue #20026 has been updated by arian (Arian Faurtosh).


Actually I see what's going on here, this can be closed, not actually a ruby issue.

`FooError || BarError` is evaluating to `FooError`

----------------------------------------
Bug #20026: Ruby doesn't throw a syntax error when rescuing with ||
https://bugs.ruby-lang.org/issues/20026#change-105446

* Author: arian (Arian Faurtosh)
* Status: Open
* Priority: Normal
* ruby -v: ruby 3.2.0 (2022-12-25 revision a528908271) [arm64-darwin23]
* Backport: 3.0: UNKNOWN, 3.1: UNKNOWN, 3.2: UNKNOWN
----------------------------------------
We had a coworker new to ruby try an interesting syntax for rescue that doesn't result in a syntax error, and works partially.

Why does ruby allow the logical OR || operator, is there a purpose for this? If not this feels like it should be a syntax error, instead of resulting in partially working code.

``` ruby
class FooError < StandardError; end
class BarError < StandardError; end

# works
begin
  raise FooError
rescue FooError || BarError => e
  puts "rescued #{e.class}"
end

# doesn't work
begin
  raise FooError
rescue FooError || BarError => e
  puts "rescued #{e.class}"
end
```




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