[ruby-core:108347] [Ruby master Feature#18685] Enumerator.product: Cartesian product of enumerables

Issue #18685 has been updated by Eregon (Benoit Daloze).


And between writing `Enumerator.product` in Ruby or C I'd prefer a lot in Ruby because it's a million times more readable, and it can be reused by other Ruby implementations :)

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Feature #18685: Enumerator.product: Cartesian product of enumerables
https://bugs.ruby-lang.org/issues/18685#change-97372

* Author: knu (Akinori MUSHA)
* Status: Open
* Priority: Normal
* Target version: 3.2
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I'd like to add a new Enumerator class method for generating the Cartesian product of given enumerators.
A product here does not mean an accumulated array of arrays, but an enumerator to enumerate all combinations.

```ruby
product = Enumerator.product(1..3, ["A", "B"])
p product.class #=> Enumerator

product.each do |i, c|
  puts "#{i}-#{c}"
end

=begin output
1-A
1-B
2-A
2-B
3-A
3-B
=end
```

This can be used to reduce nested blocks and allows for iterating over an indefinite number of enumerable objects.

## Implementation notes

- It should internally use `each_entry` instead of `each` on enumerable objects to make sure to capture all yielded arguments.
- If no enumerable object is given, the block is called once with no argument.
- It should reject a keyword-style hash argument so we can add keyword arguments in the future without breaking existing code.
- Here's an example implementation:

  ```ruby
  # call-seq:
  #   Enumerator.product(*enums)                   -> enum
  #   Enumerator.product(*enums) { |*args| block } -> return value of args[0].each_entry {}
  def Enumerator.product(*enums, **nil, &block)
   # TODO: size should be calculated if possible
    return to_enum(__method__, *enums) if block.nil?

    enums.reverse.reduce(block) { |inner, enum|
      ->(*values) {
        enum.each_entry { |value|
          inner.call(*values, value)
        }
      }
    }.call()
  end
  ```

- Not to be confused with `Enumerator.produce`. 

## Prior case
- Python: https://docs.python.org/3/library/itertools.html#itertools.product




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