From: bughit.github@... Date: 2021-07-19T19:56:32+00:00 Subject: [ruby-core:104648] [Ruby master Feature#18040] Why should `foo(1 if true)` be an error? Issue #18040 has been updated by bughit (bug hit). jeremyevans0 (Jeremy Evans) wrote in #note-4: > You may want to read the definition of `stmt` in parse.y, particularly this part: https://github.com/ruby/ruby/blob/eed5e8f796ab18e2e0a436dab83e35504ae3ded0/parse.y#L1481 You can call it a statement all you want but if it produces a value, its an expression. And it does produce produce a value. Here's the description of method return from "the ruby programming language" book: > If a method terminates normally, then the value of the method invocation expression is the value of the last expression evaluated within the method body. the last expression in my example is `1 if false` with no parens ---------------------------------------- Feature #18040: Why should `foo(1 if true)` be an error? https://bugs.ruby-lang.org/issues/18040#change-92957 * Author: bughit (bug hit) * Status: Open * Priority: Normal ---------------------------------------- There's no ambiguity here that should require another set of parens `foo((1 if true))` -- https://bugs.ruby-lang.org/ Unsubscribe: <mailto:ruby-core-request@ruby-lang.org?subject=unsubscribe> <http://lists.ruby-lang.org/cgi-bin/mailman/options/ruby-core>